题解 | #统计每种性别的人数#

select
    substring_index (profile, ',', -1) as gender,
    count(*) as number
from
    user_submit
group by
    gender;

select
    case
        when profile like '%,male' then 'male'
        when profile like '%,female' then 'female'
        else '其他'
    end as gender,
    count(*) as number
from
    user_submit
group by gender;

substring_index其实挺好用的