题解 | #获得月份天数#

#include<stdio.h>
void judge_leap_year(int y, int m, int* days1,int* days2) {
    if (((y % 4 == 0 ) && (y % 100 != 0))|| (y % 400 == 0))
        printf("%d\n", days1[m]);
    else {
        printf("%d\n", days2[m]);
    }
}
//1  2          3  4  5  6  7  8  9  10  11  12
//31 28（平年） 31 30 31 30 31 31 30 31  30  31 Regular_year
//31 29（闰年） 31 30 31 30 31 31 30 31  30  31 Leap_year

int main() 
{
  //数组首元素用0，正好数组的下标对齐月份
    int days1[13] = { 0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    int days2[13] = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
    int year = 0;
    int month = 0;
    while(scanf("%d %d", &year, &month)!=EOF)
    judge_leap_year(year, month, days1,days2);
    return 0;
}