题解 | #删除链表的倒数第n个节点#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
#
# @param head ListNode类
# @param n int整型
# @return ListNode类
#
class Solution:
    def removeNthFromEnd(self, head: ListNode, n: int) -> ListNode:
        # write code here
        length = 0
        cur = head
        # get the length of the listnodes
        while cur:
            cur = cur.next
            length += 1
        # set up a pre node for return
        pre = cur = ListNode(0)
        pre.next = head
        for _ in range(length - n):
            cur = cur.next
        cur.next = cur.next.next
        return pre.next