题解 | #数组元素处理#

#include <iostream>
using namespace std;

void func(int* p, int n);

int main() {

    int arr[6] = { 0 };
    for (int i = 0; i < 6; i++) {
        cin >> arr[i];
    }

    func(arr, 6);

    for (int i = 0; i < 6; i++) {
        if (i == 5) {
            cout << arr[i] << endl;
        }
        else {
            cout << arr[i] << " ";
        }
    }

    return 0;
}

void func(int* p, int n) {

    // write your code here......
    int id = 0;// id指向当前可以存储非0元素的位置
    for (int i = 0; i < n; i++) {
        if (p[i] != 0) {
            p[id] = p[i];
            id++;
        }
    }
    //将id和之后的元素全部赋值为0
    for (; id < n; id++) {
        p[id] = 0;
    }
    

}