题解 | #删除有序链表中重复的元素-I#快慢指针

删除有序链表中重复的元素-I

https://www.nowcoder.com/practice/c087914fae584da886a0091e877f2c79

import java.util.*;

/*
 * public class ListNode {
 *   int val;
 *   ListNode next = null;
 *   public ListNode(int val) {
 *     this.val = val;
 *   }
 * }
 */

public class Solution {
    /**
     * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
     *
     *
     * @param head ListNode类
     * @return ListNode类
     */
    public ListNode deleteDuplicates (ListNode head) {
      ListNode slowNode = head;
        if (slowNode == null) {
            return head;
        }
        ListNode fastNode = head.next;
        while (fastNode != null) {
            if (fastNode.val == slowNode.val){
                slowNode.next = fastNode.next;
                fastNode = fastNode.next;
            }else {
                slowNode = fastNode;
                fastNode = fastNode.next;
            }

        }
        return head;
    }
}

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