题解 | #删除有序链表中重复的元素-I#快慢指针
删除有序链表中重复的元素-I
https://www.nowcoder.com/practice/c087914fae584da886a0091e877f2c79
import java.util.*;
/*
* public class ListNode {
* int val;
* ListNode next = null;
* public ListNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param head ListNode类
* @return ListNode类
*/
public ListNode deleteDuplicates (ListNode head) {
ListNode slowNode = head;
if (slowNode == null) {
return head;
}
ListNode fastNode = head.next;
while (fastNode != null) {
if (fastNode.val == slowNode.val){
slowNode.next = fastNode.next;
fastNode = fastNode.next;
}else {
slowNode = fastNode;
fastNode = fastNode.next;
}
}
return head;
}
}
