题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param head ListNode类
# @return ListNode类
#
class Solution:
def ReverseList(self , head: ListNode) -> ListNode:
# write code here
if not head or not head.next:
return head
stack = []
cur = head
while cur:
stack.append(cur)
nxt = cur.next
cur.next = None
cur = nxt
node = stack.pop()
cur = node
while stack:
cur.next = stack.pop()
cur = cur.next
return node
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