题解 | #反转链表#

反转链表

https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @return ListNode类
#
class Solution:
    def ReverseList(self , head: ListNode) -> ListNode:
        # write code here
        if not head or not head.next:
            return head
        stack = []
        
        cur = head
        while cur:
            stack.append(cur)
            nxt = cur.next
            cur.next = None
            cur = nxt
        node = stack.pop()
        cur = node
        while stack:
            cur.next = stack.pop()
            cur = cur.next
        return node

全部评论

相关推荐

评论
点赞
收藏
分享

创作者周榜

更多
牛客网
牛客网在线编程
牛客网题解
牛客企业服务