题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include <stdio.h>
int main() {
int n=0;
while (scanf("%d\n", &n) != EOF)
{
printf("%d\n",1<<n);
}
return 0;
}
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