题解 | #反转链表#
反转链表
https://www.nowcoder.com/practice/75e878df47f24fdc9dc3e400ec6058ca
import java.util.*; /* * public class ListNode { * int val; * ListNode next = null; * public ListNode(int val) { * this.val = val; * } * } */ /** * 使用递归的方式解决 **/ public class Solution { /** * 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 * * * @param head ListNode类 * @return ListNode类 */ public ListNode ReverseList (ListNode head) { // write code here if(head == null){ return null; } ListNode cur = head; while(cur.next != null){ cur = cur.next; } head = reverse(head); head.next = null; return cur; } public ListNode reverse(ListNode cur){ if(cur.next == null){ return cur; }else{ ListNode next = reverse(cur.next); next.next = cur; return cur; } } }