题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
https://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
import sys
for line in sys.stdin:
n = int(line)#三行输入
nodelist = input().split()
k = int(input())
if k > n:
print('null')
else:
print(nodelist[-k])
