HJ2题解 | #计算某字符出现次数#

#include <cctype>
#include <iostream>
using namespace std;

int main() {
    string input;
    getline(cin, input);
    char targetChar;
    cin >> targetChar;
    int count = 0;
    char upperCh = toupper(targetChar); //效率问题，单提出来
    char lowerCh = tolower(targetChar);
    for (int i = 0; i < input.size(); i++) {
        if (input[i] ==  upperCh || input[i] == lowerCh) {
            ++count;
        }
    }
    cout << count << endl;
    return 0;
}
// 64 位输出请用 printf("%lld")