题解 | #牛牛的链表删除#

牛牛的链表删除

https://www.nowcoder.com/practice/d3df844baa8a4c139e103ca1b1faae0f

#include <iostream>
using namespace std;

struct ListNode {
    int val;
    ListNode* next;
    ListNode(int x) : val(x), next(NULL) {}
};

ListNode* createLinkedList(int arr[], int n) {
    if (n == 0) {
        return NULL;
    }

    ListNode* head = new ListNode(arr[0]);
    ListNode* curr = head;

    for (int i = 1; i < n; i++) {
        curr->next = new ListNode(arr[i]);
        curr = curr->next;
    }

    return head;
}

ListNode* removeElements(ListNode* head, int val) {
    ListNode* dummy = new ListNode(0);
    dummy->next = head;

    ListNode* prev = dummy;
    ListNode* curr = head;

    while (curr != NULL) {
        if (curr->val == val) {
            prev->next = curr->next;
            delete curr;
            curr = prev->next;
        } else {
            prev = curr;
            curr = curr->next;
        }
    }

    head = dummy->next;
    delete dummy;

    return head;
}

void printLinkedList(ListNode* head) {
    ListNode* curr = head;

    while (curr != NULL) {
        cout << curr->val << " ";
        curr = curr->next;
    }
    cout << endl;
}

int main() {
    int n, x;
    cin >> n >> x;

    int* arr = new int[n];

    for (int i = 0; i < n; i++) {
        cin >> arr[i];
    }

    ListNode* head = createLinkedList(arr, n);
    head = removeElements(head, x);
    printLinkedList(head);

    delete[] arr;

    ListNode* curr = head;
    ListNode* next = NULL;

    while (curr != NULL) {
        next = curr->next;
        delete curr;
        curr = next;
    }

    return 0;
}

全部评论

相关推荐

想按时下班的大菠萝在...:隔壁学校的,加油多投, 实在不好找可以下个学期开学找,把算法八股准备好,项目有空再换换
投了多少份简历才上岸
点赞 评论 收藏
分享
投递地平线等公司10个岗位
点赞 评论 收藏
分享
评论
点赞
收藏
分享

创作者周榜

更多
牛客网
牛客网在线编程
牛客网题解
牛客企业服务