题解 | #字符串通配符#

const readline = require("readline");

const rl = readline.createInterface({
    input: process.stdin,
    output: process.stdout,
});

/**
 * *：匹配0个或以上的字符（注：能被*和?匹配的字符仅由英文字母和数字0到9组成，下同）
 *  ？：匹配1个字符
 */

let row = 0;
let reg = undefined;
let line1 = undefined;

rl.on("line", function (line) {
    row++;
    if (row == 1) {
        line1 = line;
        reg = new RegExp(
            '^' + line
                .toLocaleLowerCase()
                .replace(/\?/g, "[a-z0-9\.]{1}")
                .replace(/\*+/g, "*")
                .replace(/\*/g, "[a-z0-9\.]{0,}")
            + '$',
            "i"
        );
    } else {
        console.log(reg.test(line));
    }
});