题解 | #牛牛的线段#
牛牛的线段
https://www.nowcoder.com/practice/f72c56ed71664af082c921bf79861c85
#include <stdio.h> #include<math.h> int main() { int x1, y1, x2, y2; scanf("%d %d", &x1, &y1); getchar(); scanf("%d %d", &x2, &y2); int ret = 0; ret = pow((x1 - x2), 2) + pow((y1 - y2), 2); printf("%d\n", ret); return 0; }