题解 | #旋转数组的最小数字#

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param nums int整型一维数组 
# @return int整型
#
class Solution:

    def find(self,nums,start,end):
        if start>=end:
            return nums[start]
        pivot = int((start+end)/2)

        if nums[pivot] > nums[end]:
            return self.find(nums,pivot+1,end)
        elif nums[pivot]<nums[end]:
            return self.find(nums,start,pivot)
        else:
            left = self.find(nums,start,pivot)
            right = self.find(nums,pivot+1,end)
            if left >= right:
                return right
            else:
                return left


    def minNumberInRotateArray(self , nums: List[int]) -> int:
        return self.find(nums,0,len(nums)-1)