题解 | #链表中环的入口结点#
链表中环的入口结点
https://www.nowcoder.com/practice/253d2c59ec3e4bc68da16833f79a38e4
# -*- coding:utf-8 -*-
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
# 这里可以观察到每个节点的值是有顺序的,因此可以设置一个计数器,通过判断节点值的方法来判断是否有环
class Solution:
def EntryNodeOfLoop(self, pHead):
count = 1
while pHead != None:
if pHead.val < count:
return pHead
pHead = pHead.next
count += 1
return None

