题解 | #字符串变形#
字符串变形
https://www.nowcoder.com/practice/c3120c1c1bc44ad986259c0cf0f0b80e
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param s string字符串 # @param n int整型 # @return string字符串 # class Solution: def trans(self, s: str, n: int) -> str: # write code here ls=[] l1=[] for i in s: if i.islower(): ls.append(i.upper()) elif i.isupper(): ls.append(i.lower()) else: ls.append(i) l="".join(ls).split(" ") for i in range(len(l),0,-1): l1.append(l[i-1]) a=" ".join(l1) return a