题解 | #牛牛的三元组问题#
牛牛的三元组问题
https://www.nowcoder.com/practice/72c6d735fb1144a2ba162976a4510839
#先排序,再遍历找出符合的解,将解排序判断是否在已有解集合中,不在就加入,最后将解集合排序返回 #coding:utf-8 # # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param nums int整型一维数组 # @return int整型二维数组 # class Solution: def findTriplets(self , nums ): # print(nums) sorted(nums) res=[] for i in range(len(nums)): for j in range(i+1,len(nums)): for k in range(j+1,len(nums)): if int(nums[i])+int(nums[j])+int(nums[k])==0: if sorted([int(nums[i]),int(nums[j]),int(nums[k])]) not in res: res.append(sorted([int(nums[i]),int(nums[j]),int(nums[k])])) return sorted(res) # write code here