题解 | #牛牛的循环牧场#
牛牛的循环牧场
https://www.nowcoder.com/practice/a651e248e5ad46ccb0a56a0e4e538113
class Solution {
public:
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param nums int整型vector
* @return bool布尔型
*/
int nextstep(vector<int>& nums, int curr_step){
int temp = (curr_step + nums[curr_step]);
if ( temp < 0) {
curr_step = temp + nums.size();
}
else if( temp >= nums.size()){
curr_step = (temp - nums.size());
}
else {
curr_step = temp;
}
return curr_step;
}
bool get_sign(int num){
if (num < 0) return false;
else return true;
}
bool set_state(int index, vector<int>& nums, vector<bool>& state, bool sign){
state[index] = true;
int next = nextstep(nums, index);
if ((sign ^ get_sign(nums[next]))) return false;
if (next == index) return false;
if (state[next] == true) return true;
return set_state(next, nums, state, sign);
}
bool checkCircularArray(vector<int>& nums) {
// write code here
for(int i = 0; i < nums.size(); ++i){
vector<bool> state(nums.size(), false);
bool sign = get_sign(nums[i]);
if (set_state(i, nums, state, sign)) return true;
}
return false;
}
};
