题解 | #Johnson Counter#
Johnson Counter
https://www.nowcoder.com/practice/7ee6e9ed687c40c3981d7586a65bc22d
`timescale 1ns/1ns
module JC_counter(
input clk ,
input rst_n,
output reg [3:0] Q
);
reg [7:0]temp;
always@(posedge clk or negedge rst_n)begin
if(!rst_n)begin
temp<= 8'b0111_1000;
Q <= 4'b0000;
end
else begin
temp<={temp[0],temp[7:1]};
Q <= temp[3:0];
end
end
endmodule
极简。
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