题解 | #数字颠倒#
数字颠倒
https://www.nowcoder.com/practice/ae809795fca34687a48b172186e3dafe
#include <iostream>
using namespace std;
int main() {
string str;
cin >> str;
int n = str.size();
for (int i = n - 1; i >= 0; i--) {
cout << str[i];
}
}
// 64 位输出请用 printf("%lld")
与字符串逆序解题思路相同