题解 | #2的幂#
2的幂
https://www.nowcoder.com/practice/4a04240fd2be4e1287aab4af067f6d8f
# # 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可 # # # @param n int整型 # @return bool布尔型 # class Solution: def poweroftwo(self , n: int) -> bool: # write code here if n==0: return False else: lst1=[] for i in str(bin(n)): lst1.append(i) lst1.pop(0) lst1.pop(0) for i in range(1,len(lst1)): if lst1[i] == '1': return False return True