题解 | #有序序列判断#
有序序列判断
https://www.nowcoder.com/practice/22e87f8a8d764a6582710f38d1b40c6e
import java.util.Scanner; // 注意类名必须为 Main, 不要有任何 package xxx 信息 public class Main { public static void main(String[] args) { Scanner in = new Scanner(System.in); int n = in.nextInt(); int[] a = new int[n]; for (int i = 0; i < n; i++) { int x = in.nextInt(); a[i] = x; } int q = 0; for (int i = 0; i < n; i++) { if (i < n - 1) { if (a[1] < a[0]) { for(int j=i+1;j<n;j++){ if(a[i]<a[j]){ break; }else{ q += 1; } } } else { for (int j = i + 1; j < n; j++) { if (a[i] > a[j]) { break; } else { q += 1; } } } } } if (q == (n * (n - 1)) / 2) { System.out.println("sorted"); } else { System.out.println("unsorted"); } } }