代码运行正确 | #国庆期间近7日日均取消订单量#
国庆期间近7日日均取消订单量
https://www.nowcoder.com/practice/2b330aa6cc994ec2a988704a078a0703
with a as ( select date(order_time) as dt ,sum(if(mileage >0,1,0)) as finish_cnt ,sum(if(mileage is null,1,0)) as cancel_cnt # ,count(if(mileage is null,order_id,"")) as cancel_cnt # if的空也会计数,导致统计错误,所以不能这么使用 from tb_get_car_order where date(order_time) between '2021-09-25' and '2021-10-03' group by date(order_time) ) select t1.dt as dt ,round(avg(t2.finish_cnt),2) as finish_num_7d ,round(avg(t2.cancel_cnt),2) as cancel_num_7d from a as t1,a as t2 where datediff(t1.dt,t2.dt) between 0 and 6 # 不可以用0<=datediff<=6 and t1.dt between '2021-10-01' and '2021-10-03' group by t1.dt order by dt
1.首先构建中间表,统计每日的完成订单数,取消订单数。(选取是否有里程数作为订单判断标准)
2.通过中间表自连接,用where过滤数据为10-1——10.3日这三天的近7日数据,统计平均完成订单数/平均取消订单数
3.最后细节处理,输出结果小数位数处理和日期排序