题解 | #求int型正整数在内存中存储时1的个数#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    while ((line = await readline())) {
        let k = Number(line);
        let count = 0;
        if(k == 0) {
            console.log(0);
            return;
        }
        if(k == 1) {
            console.log(++count);
            return;
        }
        for (let i = 1; k >= 2; i++) {
			// 如果 k 有余数，也就是 n == 1，那么前一位一定是 1
            n = k % 2;
            k = Math.floor(k / 2);
            if(n == 1) {
                count++;
                continue;
            }
        }
		// 循环中最后一次执行有可能会存在 k == 1的情况，说明最高位是 1
        if(k == 1) {
            console.log(++count);
            return;
        }
    }
})();