题解 | #求最大连续bit数#

import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
      public static void main(String[] args) {
         Scanner scanner = new Scanner(System.in);
        while (scanner.hasNextInt()){
            int n = scanner.nextInt();
            int count = 0;
            int maxcount = 0;
            String s = Integer.toBinaryString(n);
            for (int i = 0; i < s.length(); i++) {
                if (s.charAt(i)=='1'){
                    count++;
                }else {
                    maxcount = Math.max(count,maxcount);
                    count = 0;
                }
            }
            System.out.println(Math.max(count,maxcount));
        }
      }
}