题解 | #比较版本号#
比较版本号
https://www.nowcoder.com/practice/2b317e02f14247a49ffdbdba315459e7
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
# 比较版本号
# @param version1 string字符串
# @param version2 string字符串
# @return int整型
#
class Solution:
def compare(self , version1: str, version2: str) -> int:
# write code here
ver1 = [int(x) for x in version1.split('.')]
ver2 = [int(x) for x in version2.split('.')]
len1 = len(ver1)
len2 = len(ver2)
if len1>len2:
length = len1
while len2<len1:
len2 += 1
ver2.append(0)
else:
length = len2
while len1<len2:
len1 += 1
ver1.append(0)
ver_num1 = 0
ver_num2 = 0
for i in range(length):
ver_num1 = ver_num1*10 + ver1[i]
ver_num2 = ver_num2*10 + ver2[i]
if ver_num1 > ver_num2:
return 1
elif ver_num1 < ver_num2:
return -1
else:
return 0
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