题解 | #删除链表的节点#

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 *	ListNode(int x) : val(x), next(nullptr) {}
 * };
 */
class Solution {
public:
    /**
     * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
     *
     * 
     * @param head ListNode类 
     * @param val int整型 
     * @return ListNode类
     */
    ListNode* deleteNode(ListNode* head, int val) {
        if(head == nullptr)
            return nullptr;
        ListNode* p = head,
                * q = head;

        while(p)
        {
            if(p->val == val)
                break;

            q = p;
            p = p->next;
        }
        
        if(p == head)
            head = head->next;
        else if(p->next)
        {
            q->next = p->next;
            delete p;
        }

        return head;
    }
};