题解 | #提前结束的循环#
提前结束的循环
https://www.nowcoder.com/practice/b957171b6e974fb0b5dd3ef653624b52
l = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
a = int(input())
if a in l:
for s in l[:l.index(a)]:
print(s)
else:
for s in l:
print(s)
提前结束的循环
https://www.nowcoder.com/practice/b957171b6e974fb0b5dd3ef653624b52
l = [3, 45, 9, 8, 12, 89, 103, 42, 54, 79]
a = int(input())
if a in l:
for s in l[:l.index(a)]:
print(s)
else:
for s in l:
print(s)
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