题解 | #计算用户的平均次日留存率#
计算用户的平均次日留存率
https://www.nowcoder.com/practice/126083961ae0415fbde061d7ebbde453
WITH a AS (
SELECT
distinct device_id, date
FROM question_practice_detail
),
c as (
select *,RANK() OVER(PARTITION BY device_id ORDER BY date) AS rk,
DATE_ADD(date, INTERVAL 1 DAY) AS d_plus_1
from a
),
b AS (
SELECT
*,
LEAD(date, 1) OVER(PARTITION BY device_id ORDER BY date) AS act_d
FROM c
)
SELECT
COUNT(CASE WHEN act_d = d_plus_1 THEN 1 ELSE NULL END) / COUNT(1) AS avg_ret
FROM b;
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