题解 | #字符串反转#
字符串反转
https://www.nowcoder.com/practice/e45e078701ab4e4cb49393ae30f1bb04
#include <stdio.h>
int main() {
char ayy[1000];
int len;
int i;
scanf("%s",ayy);
len = strlen(ayy);
for (i = len-1; i>=0; i--)
{
printf("%c",ayy[i]);
}
return 0;
}
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