题解 | #在字符串中找出连续最长的数字串#

import java.util.List;
import java.util.ArrayList;
import java.util.Scanner;

// 注意类名必须为 Main, 不要有任何 package xxx 信息
public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        // 注意 hasNext 和 hasNextLine 的区别
        while (in.hasNext()) { // 注意 while 处理多个 case
            String a = in.nextLine();
            getMaxNum(a);
        }
    }

    private static void getMaxNum(String s1) {
        List<String> list = new ArrayList<>();
        StringBuilder sb = new StringBuilder();
        int max = 0;
        for (int i = 0; i < s1.length(); i++) {
            if (Character.isDigit(s1.charAt(i))) {
                sb.append(s1.charAt(i));
            }

            if (!Character.isDigit(s1.charAt(i)) || i == s1.length() - 1) {
                list.add(sb.toString());
                max = Math.max(max, sb.length());
                sb.setLength(0);
            }
        }
        for (String str : list) {
            if (str.length() == max) {
                System.out.print(str);
            }
        }
        System.out.println("," + max);
    }
}