题解 | #从单向链表中删除指定值的节点#

从单向链表中删除指定值的节点

https://www.nowcoder.com/practice/f96cd47e812842269058d483a11ced4f

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    // Write your code here
    while ((line = await readline())) {
        line = line.split(" ").map(Number);
        const n = line.shift();
        const link = [];
        link[0] = line.shift();
        const del = line.pop();
        for (let i = 0; i < line.length; i += 2) {
            const index = link.findIndex((element)=>element==line[i+1])
            link.splice(index+1, 0, line[i]);
        }
        link.splice(
            link.findIndex((i) => i === del),
            1
        );
        console.log(link.join(" "));
    }
})();

全部评论

相关推荐

点赞 收藏 评论
分享
牛客网
牛客企业服务