题解 | #字符串最后一个单词的长度#

#include <iostream>
#include <string>
using namespace std;

int main() {
    int a, b;
    string row;
    while (getline(cin, row)) { // 注意 while 处理多个 case
        int length = row.size();
        string::size_type pos = row.find_last_of(' ');
        if (pos == string::npos) {
            cout << length << endl;
        } else {
            cout << length - pos - 1 << endl;
        }

    }
    return 0;
}
// 64 位输出请用 printf("%lld")