题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
m=[[1,2,3],[4,5,6],[7,8,9]]
n=int(input('n='))
print([[x*n for x in i] for i in m ])
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
m=[[1,2,3],[4,5,6],[7,8,9]]
n=int(input('n='))
print([[x*n for x in i] for i in m ])
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