题解 | #字符串加解密 node环境解法#
字符串加解密
https://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
很多题目没有node的题解,贡献一道题解,但是没有写解题思路,解题思路还是挺直观的。
const readline = require('readline') const rl = readline.createInterface({ input: process.stdin, output: process.stdout }) function test(s1,s2){ let res1 = '' let res2 = '' for(let i=0;i<s1.length;i++){ if(Number(s1[i]) || s1[i] === '0'){ if(Number(s1[i]) === 9){ res1 += '0' }else{ let temp = Number(s1[i]) res1 += temp + 1 } }else{ // 首先判断字母是大写还是小写,因为要转换大小写 if(/[a-z]/.test(s1[i])){ // 如果是小写字符走这条逻辑 let n = s1[i].toUpperCase().charCodeAt() if(n === 90){ res1 += 'A' }else{ res1 += String.fromCharCode(n+1) } }else{ // 大写字符走这条逻辑 let n = s1[i].toLowerCase().charCodeAt() if(n === 122){ res1 += 'a' }else{ res1 += String.fromCharCode(n+1) } } } } for(let i=0;i<s2.length;i++){ if(Number(s2[i]) || s2[i] === '0'){ if(Number(s2[i]) === 0){ res2 += '9' }else{ let temp = Number(s2[i]) res2 += temp - 1 } }else{ // 首先判断该字符是大写还是小写 if(/[a-z]/.test(s2[i])){ // 如果小写走这条逻辑 let n = s2[i].toUpperCase().charCodeAt() if(n === 65){ res2 += 'Z' }else{ res2 += String.fromCharCode(n - 1) } }else{ // 大写走这条逻辑 let n = s2[i].toLowerCase().charCodeAt() if(n === 97){ res2 += 'z' }else{ res2 += String.fromCharCode(n - 1) } } } } console.log(res1) console.log(res2) } const arr = [] rl.on('line',function(line){ arr.push(line) }) rl.on('close',function(){ test(arr[0],arr[1]) // 可以使用字符串的charCodeAt来判断字符的ASCII码,这道题主要用到的方法就是charCodeAt,String.fromCharCode // console.log(String.fromCharCode('A'.charCodeAt())) // console.log('A'.charCodeAt()) // console.log('Z'.charCodeAt()) // console.log('a'.charCodeAt()) // console.log('z'.charCodeAt()) })