题解 | #简单密码#

b = input()
a = []
for i in range(len(b)):
    a.append(b[i:i+1])

for i in range(len(a)):
    if 97 <= ord(a[i]) <= 99:
       a[i] = 2 
    elif 100 <= ord(a[i]) <= 102:
        a[i] = 3
    elif 103 <= ord(a[i]) <= 105:
        a[i] = 4
    elif 106 <= ord(a[i]) <= 108:
        a[i] = 5
    elif 109 <= ord(a[i]) <= 111:
        a[i] = 6
    elif 112 <= ord(a[i]) <= 115:
        a[i] = 7
    elif 116 <= ord(a[i]) <= 118:
        a[i] = 8
    elif 119 <= ord(a[i]) <= 122:
        a[i] = 9
    elif 65 <= ord(a[i]) <= 89:
        a[i] = chr(ord(a[i].lower())+1)
    elif ord(a[i]) == 90:
        a[i] = 'a'
    print(a[i],end='')    

笨办法做题，知识点 ord(str)变为ascii码，chr是反过来