题解 | #牛牛的矩阵相加#
牛牛的矩阵相加
https://www.nowcoder.com/practice/730b90507602412fac90a3f106bfa0cd
m=[]
n=[]
start=1
step=1
for i in range(3):
for j in range(3):
n.append(start)
start = start +step
m.append(n)
n = []
pp=list(m)
kk=[]
ff=[]
x=int(input())
for i in range(3):
for j in range(3):
rr=pp[i][j] * x
ff.append(rr)
kk.append(ff)
ff=[]
print(kk)
n=[]
start=1
step=1
for i in range(3):
for j in range(3):
n.append(start)
start = start +step
m.append(n)
n = []
pp=list(m)
kk=[]
ff=[]
x=int(input())
for i in range(3):
for j in range(3):
rr=pp[i][j] * x
ff.append(rr)
kk.append(ff)
ff=[]
print(kk)
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