题解 | #2的n次方计算#
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include<iostream> using namespace std; int main() { int n; while (cin >> n) std::cout << (1<<n) << endl; return 0; } 1<<n就是2的n次方
2的n次方计算
https://www.nowcoder.com/practice/35a1e8b18658411388bc1672439de1d9
#include<iostream> using namespace std; int main() { int n; while (cin >> n) std::cout << (1<<n) << endl; return 0; } 1<<n就是2的n次方
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