题解 | #KiKi和酸奶#
KiKi和酸奶
https://www.nowcoder.com/practice/c7721f3a1b1a47a783974453e82cadbb
#include <stdio.h>
int main()
{
int n,m,h,a=0;
scanf("%d %d %d",&n,&h,&m);
if(m<=n*h)
{ a=n-(int)m/h;
if(m%h != 0)
printf("%d",a-1);
else if(m%h == 0)
printf("%d",a);
}
else
printf("输入错误，请重新输入！\n");
return 0;
}
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