题解 | #链表内指定区间反转#
链表内指定区间反转
https://www.nowcoder.com/practice/b58434e200a648c589ca2063f1faf58c
/**
* struct ListNode {
* int val;
* struct ListNode *next;
* };
*/
class Solution {
public:
/**
*
* @param head ListNode类
* @param m int整型
* @param n int整型
* @return ListNode类
*/
ListNode* reverseBetween(ListNode* head, int m, int n) {
ListNode* cur = head;
ListNode* pre = new ListNode(-1);
ListNode* res = pre;
pre->next = cur;
for(int i = 1;i<m;i++){
pre = cur;
cur = cur->next;
}
for(int i = m;i<n;i++){
ListNode* tmp = cur->next;
cur->next = tmp->next;
tmp->next = pre->next;
pre->next = tmp;
}
return res->next;
}
};
本题易错点:
1.前往m节点的起始循环位为1,而非0;
2.链表翻转顺序为从后向前反转,注意方向;


