题解 | #提取不重复的整数#
提取不重复的整数
http://www.nowcoder.com/practice/253986e66d114d378ae8de2e6c4577c1
先用linkedhashset获取去重的顺序数字,倒序遍历,再用springbuild拼接最后用integet转换
import java.util.LinkedHashSet; import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); while (sc.hasNext()) { String s = sc.nextLine(); LinkedHashSet<Character> set = new LinkedHashSet<>(); for (int i = s.length()-1; i >= 0; i--) { set.add(s.charAt(i)); } StringBuilder sb = new StringBuilder(); for (Character ch : set) { sb.append(ch); } System.out.println(Integer.parseInt(sb.toString())); } } }