请问Else是哪里没有配对起来
牛课网的各位大牛好，我刚刚学习C语言，有很多不懂的问题，请问知道，谢谢
请问以下程序第16行else为什么显示没有配对起来，非常感谢，在线等，小妹感谢
#include<stdio.h>
#include<math.h>
int main()
{
double a,b,c,disc,x1,x2,realpart,imagpart;
printf("The equation:\n");
scanf("%lf,%lf,%lf\n",&a,&b,&c);
if (fabs(a)<1e-6)
printf("This is not a equation\n");
else
{
disc=b*b-4*a*c;
if (fabs(disc)<=1e-6)
x1=-b/(2*a);
printf("This equation has two equal roots=%8.4f\n",x1);
else
if (fabs(disc)>1e-6)
{
x1=(-b+fabs(disc))/2;
x2=(-b-fabs(disc))/2;
printf("This equation has twp disctinc roots=%8.4f,%8.4f",x1,x2);
}
else
{
realpart=-b/2*a;
imagpart=fabs(disc)/2a;
printf("x1=%8.4f+%8.4fi",realpart,imagpart);
printf("x1=%8.4f-%8.4fi",realpart,imagpart);
}
}
return 0;
}
#include<math.h>
int main()
{
double a,b,c,disc,x1,x2,realpart,imagpart;
printf("The equation:\n");
scanf("%lf,%lf,%lf\n",&a,&b,&c);
if (fabs(a)<1e-6)
printf("This is not a equation\n");
else
{
disc=b*b-4*a*c;
if (fabs(disc)<=1e-6)
x1=-b/(2*a);
printf("This equation has two equal roots=%8.4f\n",x1);
else
if (fabs(disc)>1e-6)
{
x1=(-b+fabs(disc))/2;
x2=(-b-fabs(disc))/2;
printf("This equation has twp disctinc roots=%8.4f,%8.4f",x1,x2);
}
else
{
realpart=-b/2*a;
imagpart=fabs(disc)/2a;
printf("x1=%8.4f+%8.4fi",realpart,imagpart);
printf("x1=%8.4f-%8.4fi",realpart,imagpart);
}
}
return 0;
}
查看30道真题和解析