题解 | #字符串加解密#

#include <string>

using namespace std;

void myfunc(string code){
    string tempstr;
    int distance;
    //小写大，大写小
    distance = 'a' - 'A';

    for (int i = 0; i < code.size(); ++i) {
        if (code[i]>'a'-1&&code[i]<'z'+1){
            //小写字母
            if (code[i] == 'z'){
                tempstr.push_back('A');
            } else{
                int a = code[i] + 0;
                tempstr.push_back(a-distance+1);
            }
        } else if (code[i]>'A'-1&&code[i]<'Z'+1){
            //大写字母
            if (code[i] == 'Z'){
                tempstr.push_back('a');
            } else{
                int a = code[i] + 0;
                tempstr.push_back(a+distance+1);
            }
        } else if (code[i]>'0'-1&&code[i]<'9'+1){
            //数字
            if (code[i] == '9'){
                tempstr.push_back('0');
            } else{
                int temppp = code[i] - '0';
                tempstr.push_back('0'+1+temppp);
            }
        } else{
            //其他不变
            tempstr.push_back(code[i]);
        }
    }
    cout << tempstr << endl;
}

void myversefunc(string cipher){
    string tempstr;
    int distance;
    //小写大，大写小
    distance = 'a' - 'A';

    for (int i = 0; i < cipher.size(); ++i) {
        if (cipher[i]>'a'-1&&cipher[i]<'z'+1){
            //小写字母
            if (cipher[i] == 'a'){
                tempstr.push_back('Z');
            } else{
                int a = cipher[i] + 0;
                tempstr.push_back(a-distance-1);
            }
        } else if (cipher[i]>'A'-1&&cipher[i]<'Z'+1){
            //大写字母
            if (cipher[i] == 'A'){
                tempstr.push_back('z');
            } else{
                int a = cipher[i] + 0;
                tempstr.push_back(a+distance-1);
            }
        } else if (cipher[i]>'0'-1&&cipher[i]<'9'+1){
            //数字
            if (cipher[i] == '0'){
                tempstr.push_back('9');
            } else{
                int temppp = cipher[i] - '0';
                tempstr.push_back('0'-1+temppp);
            }
        } else{
            //其他不变
            tempstr.push_back(cipher[i]);
        }
    }
    cout << tempstr << endl;
}

int main() {
    string code;
    string cipher;
    getline(cin,code);
    getline(cin,cipher);


    myfunc(code);
    myversefunc(cipher);
    return 0;
}
//解密编写完毕，明天编写逆解密

ASCII码好好用就行，一个处理字符的没有技巧的题