题解 | #提取不重复的整数#

#include<string>
using namespace std;
int main()
{
    int arr[10] = {0};
    string str;
    cin >> str;
    int size = str.size();
    for(int i = size - 1; i >= 0; i--)
    {
        int b = str[i] - '0';
        if(arr[b] == 0)
        {
            arr[b] ++;
            cout << str[i];
        }
    }
    return 0;
}