题解 | #二叉树的后序遍历#
二叉树的后序遍历
http://www.nowcoder.com/practice/1291064f4d5d4bdeaefbf0dd47d78541
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类
* @return int整型一维数组
*/
List<Integer> list = new ArrayList<>();
public int[] postorderTraversal (TreeNode root) {
// write code here
TreeNode node = root;
//常规非递归
// Stack<TreeNode> stack = new Stack<>();
// TreeNode pre = null;
// while(node != null || !stack.isEmpty()){
// while(node != null){
// stack.push(node);
// node = node.left;
// }
// node = stack.pop();
// if(node.right == null || node.right == pre){
// list.add(node.val);
// pre = node;
// node = null;
// }else{
// stack.push(node);
// node = node.right;
// }
// }
//morris遍历
while(node != null){
if(node.left != null){
TreeNode cur = node.left;
while(cur.right != null && cur.right != node){
cur = cur.right;
}
if(cur.right != node){
cur.right = node;
node = node.left;
}else{
cur.right = null;
postMorris(node.left);
node = node.right;
}
} else{
postMorris(node.left);
node = node.right;
}
}
postMorris(root);
int[] arrays = new int[list.size()];
int i = 0;
for(int l : list){
arrays[i++] = l;
}
return arrays;
}
public void postMorris(TreeNode root){
TreeNode node = reverseList(root);
TreeNode cur = node;
while(cur != null){
list.add(cur.val);
cur = cur.right;
}
reverseList(node);
}
public TreeNode reverseList(TreeNode root){
TreeNode cur = root;
TreeNode pre = null;
while(cur != null){
TreeNode node = cur.right;
cur.right = pre;
pre = cur;
cur = node;
}
return pre;
}
}
