题解 | #尼科彻斯定理#

#include<bits/stdc++.h>
using namespace std;
int main() {
    int a;
    while (cin >> a) {
        int b = a * (a - 1) + 1;
        for (int i = 0; i < a; ++i) {
            if (i == a - 1)    cout << b << endl;
            else {
                cout << b << '+';
                b += 2;
            }
        }
    }
}```