题解 | #n的阶乘#
n的阶乘
http://www.nowcoder.com/practice/97be22ee50b14cccad2787998ca628c8
#include<iostream>
using namespace std;
long long Fact(int n) {
if(n == 1) {
return 1;
}
return n*Fact(n-1);
}
int main() {
int n;
while(scanf("%d",&n) != EOF){
printf("%lld\n",Fact(n));
}
}
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