题解 | #记负均正#

let numStr, inputCount = 0;

while (line = readline()) {
    inputCount++;
    if (inputCount % 2 === 0) {// 判断 第几次输入，2整除的话是第二次输入
        let arr = line.split(' ').map(item => parseInt(item));
        output(parseInt(numStr), arr)        
    } else {
        numStr = line
    }
}

function output(num, arr) {
    let len = arr.length;

    let sum = 0.0;
    let avage = sum;
    let count = 0;// 正整数的个数
    arr.map((item, index) => {
        if (item > 0) {
            sum += item
            count++
        }
        // 如果没有正整数
        if (index === arr.length - 1 && count !== 0) {
            avage = sum/count
        }
    })
    
    let fushuArr = arr.filter(item => item < 0)// 负整数数组
    console.log(fushuArr.length, avage.toFixed(1));
}
// 测试用例
// 5
// -1 -2 3 4 5