题解 | #单词消消乐#
单词消消乐
http://www.nowcoder.com/practice/abb14fd6e1a34b0fb8016dfd7a99dfc5
#
# 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
#
#
# @param Words string字符串一维数组
# @return string字符串
#
class Solution:
def WordsMerge(self, Words):
# write code here
tmp = ''
tmp2 = ''
for i in range(0, len(Words)):
if i == 0:
tmp = Words[0]
else:
tmp = tmp[::-1]
a = len(tmp)
tmp2 = Words[i]
while a > 0:
if tmp[0] == tmp2[0]:
tmp = tmp[1:]
tmp2 = tmp2[1:]
a -= 1
tmp = tmp[::-1] + tmp2
return tmp