题解 | #平衡二叉树#

平衡二叉树

http://www.nowcoder.com/practice/8b3b95850edb4115918ecebdf1b4d222

# -*- coding:utf-8 -*-
# class TreeNode:
#     def __init__(self, x):
#         self.val = x
#         self.left = None
#         self.right = None
class Solution:
    def maxdep(self,root):
        if root==None :
            return 0
        return max(self.maxdep(root.left),self.maxdep(root.right))+1
    def IsBalanced_Solution(self, pRoot):
        # write code here
        if pRoot is None:
            return True
        if abs(self.maxdep(pRoot.left)-self.maxdep(pRoot.right))>1:
            return False
        return self.IsBalanced_Solution(pRoot.left) and self.IsBalanced_Solution(pRoot.right)
        
        
全部评论

相关推荐

点赞 评论 收藏
转发
1 收藏 评论
分享
牛客网
牛客企业服务